Luna/kernel/include/sys/UserMemory.h
apio 27448611b3 UserMemory: do not map refs into kernel memory
This is bad design. But it fails if mapped, since something overwrites KernelHeap.
2022-10-20 18:50:07 +02:00

43 lines
1.3 KiB
C++

#pragma once
#ifndef MODULE
#define MODULE "mem"
#endif
#include "log/Log.h"
#include "memory/MemoryManager.h"
#include "memory/VMM.h"
#include "misc/utils.h"
char* strdup_from_user(const char* user_string);
// FIXME: Map the physical addresses into kernel address space. Right now, something overwrites KernelHeap and crashes
// it, so that's not really possible. But it should be done in the future.
template <typename T, unsigned long S = sizeof(T), typename V> T* user_address_to_typed_pointer(V address)
{
uint64_t phys = VMM::get_physical((uint64_t)address);
if (phys == (uint64_t)-1)
{
kinfoln("warning: user pointer is not mapped in its address space");
return nullptr;
}
// return (T*)MemoryManager::get_unaligned_mappings((void*)phys, Utilities::get_blocks_from_size(PAGE_SIZE, S),
// MAP_READ_WRITE);
return (T*)phys;
}
template <typename T, unsigned long S = sizeof(T)> void free_user_typed_pointer(T*)
{
// MemoryManager::release_unaligned_mappings(ptr, Utilities::get_blocks_from_size(PAGE_SIZE, S));
}
template <typename T> T* obtain_user_ref(T* user_ptr)
{
return user_address_to_typed_pointer<T>(user_ptr);
}
template <typename T> void release_user_ref(T* ptr)
{
return free_user_typed_pointer(ptr);
}